Base | Representation |
---|---|
bin | 1010111011001000011111… |
… | …1111000000100100000001 |
3 | 1120112020111221100010000221 |
4 | 2232302013333000210001 |
5 | 3033242022030014103 |
6 | 41313440512343041 |
7 | 2346524011331152 |
oct | 256620777004401 |
9 | 46466457303027 |
10 | 12011010001153 |
11 | 3910928023709 |
12 | 141b992b44a81 |
13 | 691830709477 |
14 | 2d749bd33929 |
15 | 15c6797d81bd |
hex | aec87fc0901 |
12011010001153 has 2 divisors, whose sum is σ = 12011010001154. Its totient is φ = 12011010001152.
The previous prime is 12011010001093. The next prime is 12011010001187. The reversal of 12011010001153 is 35110001011021.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10785490152129 + 1225519849024 = 3284127^2 + 1107032^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011010001153 - 217 = 12011009870081 is a prime.
It is a super-2 number, since 2×120110100011532 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12011010001453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005505000576 + 6005505000577.
It is an arithmetic number, because the mean of its divisors is an integer number (6005505000577).
Almost surely, 212011010001153 is an apocalyptic number.
It is an amenable number.
12011010001153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011010001153 is an equidigital number, since it uses as much as digits as its factorization.
12011010001153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 16.
Adding to 12011010001153 its reverse (35110001011021), we get a palindrome (47121011012174).
The spelling of 12011010001153 in words is "twelve trillion, eleven billion, ten million, one thousand, one hundred fifty-three".
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