Base | Representation |
---|---|
bin | 10001011110100111010… |
… | …000100000111101101111 |
3 | 11020211020212022111202122 |
4 | 101132213100200331233 |
5 | 124134324102444413 |
6 | 2315440104143155 |
7 | 152530266355664 |
oct | 21364720407557 |
9 | 4224225274678 |
10 | 1201101999983 |
11 | 423425847a86 |
12 | 174946767abb |
13 | 893569b8ac2 |
14 | 421c2a27a6b |
15 | 2139b819108 |
hex | 117a7420f6f |
1201101999983 has 2 divisors, whose sum is σ = 1201101999984. Its totient is φ = 1201101999982.
The previous prime is 1201101999959. The next prime is 1201102000027. The reversal of 1201101999983 is 3899991011021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201101999983 - 210 = 1201101998959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201101999913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600550999991 + 600550999992.
It is an arithmetic number, because the mean of its divisors is an integer number (600550999992).
Almost surely, 21201101999983 is an apocalyptic number.
1201101999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201101999983 is an equidigital number, since it uses as much as digits as its factorization.
1201101999983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 53.
The spelling of 1201101999983 in words is "one trillion, two hundred one billion, one hundred one million, nine hundred ninety-nine thousand, nine hundred eighty-three".
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