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12011021200141 is a prime number
BaseRepresentation
bin1010111011001000100010…
…1001101110101100001101
31120112020112201102002011021
42232302020221232230031
53033242032411401031
641313441552354141
72346524205453235
oct256621051565415
946466481362137
1012011021200141
113910933382677
12141b996845951
13691832b2a9a2
142d749d60acc5
1515c67a79b511
hexaec88a6eb0d

12011021200141 has 2 divisors, whose sum is σ = 12011021200142. Its totient is φ = 12011021200140.

The previous prime is 12011021200121. The next prime is 12011021200153. The reversal of 12011021200141 is 14100212011021.

12011021200141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11692439975241 + 318581224900 = 3419421^2 + 564430^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011021200141 - 25 = 12011021200109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12011021200111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005510600070 + 6005510600071.

It is an arithmetic number, because the mean of its divisors is an integer number (6005510600071).

Almost surely, 212011021200141 is an apocalyptic number.

It is an amenable number.

12011021200141 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011021200141 is an equidigital number, since it uses as much as digits as its factorization.

12011021200141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 12011021200141 its reverse (14100212011021), we get a palindrome (26111233211162).

The spelling of 12011021200141 in words is "twelve trillion, eleven billion, twenty-one million, two hundred thousand, one hundred forty-one".