Base | Representation |
---|---|
bin | 1010111011001000111101… |
… | …0100101110001000010101 |
3 | 1120112020211112000212122001 |
4 | 2232302033110232020111 |
5 | 3033242300040231313 |
6 | 41313501031435301 |
7 | 2346530035046125 |
oct | 256621724561025 |
9 | 46466745025561 |
10 | 12011133133333 |
11 | 3910990584744 |
12 | 141ba08225b31 |
13 | 69185008bc49 |
14 | 2d74b0426c85 |
15 | 15c68550badd |
hex | aec8f52e215 |
12011133133333 has 2 divisors, whose sum is σ = 12011133133334. Its totient is φ = 12011133133332.
The previous prime is 12011133133309. The next prime is 12011133133357. The reversal of 12011133133333 is 33333133111021.
12011133133333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (12011133133309) and next prime (12011133133357).
It can be written as a sum of positive squares in only one way, i.e., 10015914732849 + 1995218400484 = 3164793^2 + 1412522^2 .
It is an emirp because it is prime and its reverse (33333133111021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12011133133333 - 25 = 12011133133301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011133133393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005566566666 + 6005566566667.
It is an arithmetic number, because the mean of its divisors is an integer number (6005566566667).
Almost surely, 212011133133333 is an apocalyptic number.
It is an amenable number.
12011133133333 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011133133333 is an equidigital number, since it uses as much as digits as its factorization.
12011133133333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 28.
Adding to 12011133133333 its reverse (33333133111021), we get a palindrome (45344266244354).
The spelling of 12011133133333 in words is "twelve trillion, eleven billion, one hundred thirty-three million, one hundred thirty-three thousand, three hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.132 sec. • engine limits •