Base | Representation |
---|---|
bin | 1010111011001001001111… |
… | …1010011100011001000010 |
3 | 1120112021000212220202120212 |
4 | 2232302103322130121002 |
5 | 3033242424243143020 |
6 | 41313512422034122 |
7 | 2346531661366136 |
oct | 256622372343102 |
9 | 46467025822525 |
10 | 12011210131010 |
11 | 3910a1aa95192 |
12 | 141ba29b78942 |
13 | 69186300a8bc |
14 | 2d74ba74b3c6 |
15 | 15c68c16acc5 |
hex | aec93e9c642 |
12011210131010 has 64 divisors (see below), whose sum is σ = 22412563440480. Its totient is φ = 4629099847680.
The previous prime is 12011210131007. The next prime is 12011210131049. The reversal of 12011210131010 is 1013101211021.
12011210131010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 16 ways, for example, as 322120948249 + 11689089182761 = 567557^2 + 3418931^2 .
It is a super-2 number, since 2×120112101310102 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 414722930 + ... + 414751890.
Almost surely, 212011210131010 is an apocalyptic number.
12011210131010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12011210131010 is a deficient number, since it is larger than the sum of its proper divisors (10401353309470).
12011210131010 is a wasteful number, since it uses less digits than its factorization.
12011210131010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31943.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 12011210131010 its reverse (1013101211021), we get a palindrome (13024311342031).
The spelling of 12011210131010 in words is "twelve trillion, eleven billion, two hundred ten million, one hundred thirty-one thousand, ten".
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