Base | Representation |
---|---|
bin | 11011010011110111001000… |
… | …110110110000101101000111 |
3 | 120202021121101212120222001002 |
4 | 123103313020312300231013 |
5 | 111220404120314343421 |
6 | 1103242430104523515 |
7 | 34204546362342014 |
oct | 3323671066605507 |
9 | 522247355528032 |
10 | 120112130231111 |
11 | 352a92a52204a7 |
12 | 1157a65148059b |
13 | 52036aa06a955 |
14 | 219365b12c70b |
15 | dd45d3787b0b |
hex | 6d3dc8db0b47 |
120112130231111 has 2 divisors, whose sum is σ = 120112130231112. Its totient is φ = 120112130231110.
The previous prime is 120112130230949. The next prime is 120112130231113. The reversal of 120112130231111 is 111132031211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120112130231111 - 218 = 120112129968967 is a prime.
Together with 120112130231113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120112130231113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056065115555 + 60056065115556.
It is an arithmetic number, because the mean of its divisors is an integer number (60056065115556).
Almost surely, 2120112130231111 is an apocalyptic number.
120112130231111 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112130231111 is an equidigital number, since it uses as much as digits as its factorization.
120112130231111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 120112130231111 its reverse (111132031211021), we get a palindrome (231244161442132).
The spelling of 120112130231111 in words is "one hundred twenty trillion, one hundred twelve billion, one hundred thirty million, two hundred thirty-one thousand, one hundred eleven".
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