Base | Representation |
---|---|
bin | 10110010111110111… |
… | …00011110001000101 |
3 | 1011000002102101210222 |
4 | 23023323203301011 |
5 | 144044344304222 |
6 | 5303512154125 |
7 | 603436361522 |
oct | 131373436105 |
9 | 34002371728 |
10 | 12011322437 |
11 | 5104095364 |
12 | 23b2698945 |
13 | 11955ca2aa |
14 | 81d328149 |
15 | 4a475a542 |
hex | 2cbee3c45 |
12011322437 has 2 divisors, whose sum is σ = 12011322438. Its totient is φ = 12011322436.
The previous prime is 12011322293. The next prime is 12011322439. The reversal of 12011322437 is 73422311021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9200838241 + 2810484196 = 95921^2 + 53014^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011322437 - 226 = 11944213573 is a prime.
Together with 12011322439, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011322439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005661218 + 6005661219.
It is an arithmetic number, because the mean of its divisors is an integer number (6005661219).
Almost surely, 212011322437 is an apocalyptic number.
It is an amenable number.
12011322437 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011322437 is an equidigital number, since it uses as much as digits as its factorization.
12011322437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 12011322437 its reverse (73422311021), we get a palindrome (85433633458).
The spelling of 12011322437 in words is "twelve billion, eleven million, three hundred twenty-two thousand, four hundred thirty-seven".
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