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12012000000031 is a prime number
BaseRepresentation
bin1010111011001100001011…
…1111100011100000011111
31120112100001221012021012001
42232303002333203200133
53033301034000000111
641314123035423131
72346560362226233
oct256630277434037
946470057167161
1012012000000031
1139112959364a9
12142000a5b4aa7
1369195a854415
142d75535da5c3
1515c6d66911c1
hexaecc2fe381f

12012000000031 has 2 divisors, whose sum is σ = 12012000000032. Its totient is φ = 12012000000030.

The previous prime is 12011999999999. The next prime is 12012000000043. The reversal of 12012000000031 is 13000000021021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12012000000031 - 25 = 12011999999999 is a prime.

It is a super-2 number, since 2×120120000000312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12011999999954 and 12012000000017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012000006031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006000000015 + 6006000000016.

It is an arithmetic number, because the mean of its divisors is an integer number (6006000000016).

Almost surely, 212012000000031 is an apocalyptic number.

12012000000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012000000031 is an equidigital number, since it uses as much as digits as its factorization.

12012000000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 12012000000031 its reverse (13000000021021), we get a palindrome (25012000021052).

The spelling of 12012000000031 in words is "twelve trillion, twelve billion, thirty-one", and thus it is an aban number and an uban number.