Base | Representation |
---|---|
bin | 11011010011111110011101… |
… | …111111010111011001010111 |
3 | 120202022100201101211111121201 |
4 | 123103332131333113121113 |
5 | 111221021230224013142 |
6 | 1103250211110453331 |
7 | 34205245413646105 |
oct | 3323763577273127 |
9 | 522270641744551 |
10 | 120120001001047 |
11 | 35301674052443 |
12 | 11580089364247 |
13 | 52043628a4878 |
14 | 2193ba6596c75 |
15 | dd48e4757ab7 |
hex | 6d3f9dfd7657 |
120120001001047 has 2 divisors, whose sum is σ = 120120001001048. Its totient is φ = 120120001001046.
The previous prime is 120120001001029. The next prime is 120120001001083. The reversal of 120120001001047 is 740100100021021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120120001001047 - 211 = 120120000998999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120120001001447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060000500523 + 60060000500524.
It is an arithmetic number, because the mean of its divisors is an integer number (60060000500524).
Almost surely, 2120120001001047 is an apocalyptic number.
120120001001047 is a deficient number, since it is larger than the sum of its proper divisors (1).
120120001001047 is an equidigital number, since it uses as much as digits as its factorization.
120120001001047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 120120001001047 its reverse (740100100021021), we get a palindrome (860220101022068).
The spelling of 120120001001047 in words is "one hundred twenty trillion, one hundred twenty billion, one million, one thousand, forty-seven".
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