120120009924989 has 2 divisors, whose sum is σ = 120120009924990. Its totient is φ = 120120009924988.

The previous prime is 120120009924961. The next prime is 120120009924991. The reversal of 120120009924989 is 989429900021021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89435700132025 + 30684309792964 = 9457045^2 + 5539342^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120120009924989 is a prime.

It is a super-3 number, since 3×120120009924989³ (a number of 43 digits) contains 333 as substring.

Together with 120120009924991, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120120009924919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060004962494 + 60060004962495.

It is an arithmetic number, because the mean of its divisors is an integer number (60060004962495).

Almost surely, 2^{120120009924989} is an apocalyptic number.

It is an amenable number.

120120009924989 is a deficient number, since it is larger than the sum of its proper divisors (1).

120120009924989 is an equidigital number, since it uses as much as digits as its factorization.

120120009924989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 56.

The spelling of 120120009924989 in words is "one hundred twenty trillion, one hundred twenty billion, nine million, nine hundred twenty-four thousand, nine hundred eighty-nine".