Base | Representation |
---|---|
bin | 1010111011001100010011… |
… | …1110101100101101001001 |
3 | 1120112100011020220121022002 |
4 | 2232303010332230231021 |
5 | 3033301121013024433 |
6 | 41314130230040345 |
7 | 2346561245434154 |
oct | 256630476545511 |
9 | 46470136817262 |
10 | 12012033329993 |
11 | 3911302730824 |
12 | 14200197a90b5 |
13 | 691964723ca8 |
14 | 2d7557bd4c9b |
15 | 15c6d95769e8 |
hex | aecc4facb49 |
12012033329993 has 2 divisors, whose sum is σ = 12012033329994. Its totient is φ = 12012033329992.
The previous prime is 12012033329897. The next prime is 12012033330001. The reversal of 12012033329993 is 39992333021021.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11570590024249 + 441443305744 = 3401557^2 + 664412^2 .
It is a cyclic number.
It is not a de Polignac number, because 12012033329993 - 210 = 12012033328969 is a prime.
It is not a weakly prime, because it can be changed into another prime (12012033829993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006016664996 + 6006016664997.
It is an arithmetic number, because the mean of its divisors is an integer number (6006016664997).
Almost surely, 212012033329993 is an apocalyptic number.
It is an amenable number.
12012033329993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012033329993 is an equidigital number, since it uses as much as digits as its factorization.
12012033329993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 472392, while the sum is 47.
The spelling of 12012033329993 in words is "twelve trillion, twelve billion, thirty-three million, three hundred twenty-nine thousand, nine hundred ninety-three".
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