120121000020113 has 2 divisors, whose sum is σ = 120121000020114. Its totient is φ = 120121000020112.

The previous prime is 120121000020083. The next prime is 120121000020127. The reversal of 120121000020113 is 311020000121021.

It is an a-pointer prime, because the next prime (120121000020127) can be obtained adding 120121000020113 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77162046661249 + 42958953358864 = 8784193^2 + 6554308^2 .

It is a cyclic number.

It is not a de Polignac number, because 120121000020113 - 2²⁰ = 120120998971537 is a prime.

It is not a weakly prime, because it can be changed into another prime (120121000026113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060500010056 + 60060500010057.

It is an arithmetic number, because the mean of its divisors is an integer number (60060500010057).

Almost surely, 2^{120121000020113} is an apocalyptic number.

It is an amenable number.

120121000020113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120121000020113 is an equidigital number, since it uses as much as digits as its factorization.

120121000020113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120121000020113 its reverse (311020000121021), we get a palindrome (431141000141134).

The spelling of 120121000020113 in words is "one hundred twenty trillion, one hundred twenty-one billion, twenty thousand, one hundred thirteen".