Base | Representation |
---|---|
bin | 1010111011001100100011… |
… | …1101000110101101110111 |
3 | 1120112100022220101212022111 |
4 | 2232303020331012231313 |
5 | 3033301240101133421 |
6 | 41314141011311451 |
7 | 2346563015340001 |
oct | 256631075065567 |
9 | 46470286355274 |
10 | 12012100021111 |
11 | 3911337341853 |
12 | 1420037bab587 |
13 | 6919754a46a8 |
14 | 2d75629d5371 |
15 | 15c6e034bee1 |
hex | aecc8f46b77 |
12012100021111 has 2 divisors, whose sum is σ = 12012100021112. Its totient is φ = 12012100021110.
The previous prime is 12012100021093. The next prime is 12012100021123. The reversal of 12012100021111 is 11112000121021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12012100021111 - 223 = 12012091632503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12012100021091 and 12012100021100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012100025111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006050010555 + 6006050010556.
It is an arithmetic number, because the mean of its divisors is an integer number (6006050010556).
Almost surely, 212012100021111 is an apocalyptic number.
12012100021111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012100021111 is an equidigital number, since it uses as much as digits as its factorization.
12012100021111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 12012100021111 its reverse (11112000121021), we get a palindrome (23124100142132).
The spelling of 12012100021111 in words is "twelve trillion, twelve billion, one hundred million, twenty-one thousand, one hundred eleven".
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