12012100200011 has 2 divisors, whose sum is σ = 12012100200012. Its totient is φ = 12012100200010.

The previous prime is 12012100199927. The next prime is 12012100200013. The reversal of 12012100200011 is 11000200121021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12012100200011 - 2¹⁴ = 12012100183627 is a prime.

It is a Sophie Germain prime.

Together with 12012100200013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012100199965 and 12012100200001.

It is not a weakly prime, because it can be changed into another prime (12012100200013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006050100005 + 6006050100006.

It is an arithmetic number, because the mean of its divisors is an integer number (6006050100006).

Almost surely, 2^{12012100200011} is an apocalyptic number.

12012100200011 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012100200011 is an equidigital number, since it uses as much as digits as its factorization.

12012100200011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 12012100200011 its reverse (11000200121021), we get a palindrome (23012300321032).

The spelling of 12012100200011 in words is "twelve trillion, twelve billion, one hundred million, two hundred thousand, eleven".