12012100200013 has 2 divisors, whose sum is σ = 12012100200014. Its totient is φ = 12012100200012.

The previous prime is 12012100200011. The next prime is 12012100200031. The reversal of 12012100200013 is 31000200121021.

Together with next prime (12012100200031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11706819639529 + 305280560484 = 3421523^2 + 552522^2 .

It is a cyclic number.

It is not a de Polignac number, because 12012100200013 - 2¹ = 12012100200011 is a prime.

Together with 12012100200011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12012100199966 and 12012100200002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012100200011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006050100006 + 6006050100007.

It is an arithmetic number, because the mean of its divisors is an integer number (6006050100007).

Almost surely, 2^{12012100200013} is an apocalyptic number.

It is an amenable number.

12012100200013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012100200013 is an equidigital number, since it uses as much as digits as its factorization.

12012100200013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12012100200013 its reverse (31000200121021), we get a palindrome (43012300321034).

The spelling of 12012100200013 in words is "twelve trillion, twelve billion, one hundred million, two hundred thousand, thirteen".