Base | Representation |
---|---|
bin | 11011010011111111011010… |
… | …001001001100010100110011 |
3 | 120202022110022201211122011202 |
4 | 123103333122021030110303 |
5 | 111221030312103210344 |
6 | 1103250455201401415 |
7 | 34205312420043413 |
oct | 3323773211142463 |
9 | 522273281748152 |
10 | 120121010210099 |
11 | 35302041796108 |
12 | 1158030b33926b |
13 | 52044939b75a2 |
14 | 2193c60620643 |
15 | dd495315794e |
hex | 6d3fda24c533 |
120121010210099 has 2 divisors, whose sum is σ = 120121010210100. Its totient is φ = 120121010210098.
The previous prime is 120121010210087. The next prime is 120121010210111. The reversal of 120121010210099 is 990012010121021.
It is a balanced prime because it is at equal distance from previous prime (120121010210087) and next prime (120121010210111).
It is an emirp because it is prime and its reverse (990012010121021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120121010210099 - 220 = 120121009161523 is a prime.
It is not a weakly prime, because it can be changed into another prime (120121010210009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060505105049 + 60060505105050.
It is an arithmetic number, because the mean of its divisors is an integer number (60060505105050).
Almost surely, 2120121010210099 is an apocalyptic number.
120121010210099 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121010210099 is an equidigital number, since it uses as much as digits as its factorization.
120121010210099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 29.
The spelling of 120121010210099 in words is "one hundred twenty trillion, one hundred twenty-one billion, ten million, two hundred ten thousand, ninety-nine".
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