Base | Representation |
---|---|
bin | 11011010011111111011010… |
… | …001001001100010100111111 |
3 | 120202022110022201211122012012 |
4 | 123103333122021030110333 |
5 | 111221030312103210421 |
6 | 1103250455201401435 |
7 | 34205312420043431 |
oct | 3323773211142477 |
9 | 522273281748165 |
10 | 120121010210111 |
11 | 35302041796119 |
12 | 1158030b33927b |
13 | 52044939b75b1 |
14 | 2193c60620651 |
15 | dd495315795b |
hex | 6d3fda24c53f |
120121010210111 has 2 divisors, whose sum is σ = 120121010210112. Its totient is φ = 120121010210110.
The previous prime is 120121010210099. The next prime is 120121010210143. The reversal of 120121010210111 is 111012010121021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120121010210111 is a prime.
It is a super-2 number, since 2×1201210102101112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120121010200111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060505105055 + 60060505105056.
It is an arithmetic number, because the mean of its divisors is an integer number (60060505105056).
Almost surely, 2120121010210111 is an apocalyptic number.
120121010210111 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121010210111 is an equidigital number, since it uses as much as digits as its factorization.
120121010210111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 120121010210111 its reverse (111012010121021), we get a palindrome (231133020331132).
The spelling of 120121010210111 in words is "one hundred twenty trillion, one hundred twenty-one billion, ten million, two hundred ten thousand, one hundred eleven".
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