Base | Representation |
---|---|
bin | 11011010011111111011010… |
… | …001100001111110110010111 |
3 | 120202022110022210100022202112 |
4 | 123103333122030033312113 |
5 | 111221030312304322332 |
6 | 1103250455230501235 |
7 | 34205312426620331 |
oct | 3323773214176627 |
9 | 522273283308675 |
10 | 120121011010967 |
11 | 3530204219288a |
12 | 1158030b66481b |
13 | 5204493c07c85 |
14 | 2193c6078c451 |
15 | dd4953264db2 |
hex | 6d3fda30fd97 |
120121011010967 has 2 divisors, whose sum is σ = 120121011010968. Its totient is φ = 120121011010966.
The previous prime is 120121011010963. The next prime is 120121011011093. The reversal of 120121011010967 is 769010110121021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120121011010967 - 22 = 120121011010963 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120121011010963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060505505483 + 60060505505484.
It is an arithmetic number, because the mean of its divisors is an integer number (60060505505484).
Almost surely, 2120121011010967 is an apocalyptic number.
120121011010967 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121011010967 is an equidigital number, since it uses as much as digits as its factorization.
120121011010967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 32.
Adding to 120121011010967 its reverse (769010110121021), we get a palindrome (889131121131988).
The spelling of 120121011010967 in words is "one hundred twenty trillion, one hundred twenty-one billion, eleven million, ten thousand, nine hundred sixty-seven".
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