12012102012319 has 2 divisors, whose sum is σ = 12012102012320. Its totient is φ = 12012102012318.

The previous prime is 12012102012233. The next prime is 12012102012389. The reversal of 12012102012319 is 91321020121021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12012102012319 - 2⁹ = 12012102011807 is a prime.

It is a super-3 number, since 3×12012102012319³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12012102012293 and 12012102012302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012102012389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051006159 + 6006051006160.

It is an arithmetic number, because the mean of its divisors is an integer number (6006051006160).

Almost surely, 2^{12012102012319} is an apocalyptic number.

12012102012319 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012102012319 is an equidigital number, since it uses as much as digits as its factorization.

12012102012319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 12012102012319 in words is "twelve trillion, twelve billion, one hundred two million, twelve thousand, three hundred nineteen".