Base | Representation |
---|---|
bin | 11011010011111111100110… |
… | …000011011010000010110110 |
3 | 120202022110211122211000212021 |
4 | 123103333212003122002312 |
5 | 111221031214231120042 |
6 | 1103250531100143354 |
7 | 34205320364306551 |
oct | 3323774603320266 |
9 | 522273748730767 |
10 | 120121210020022 |
11 | 35302134559282 |
12 | 11580366237b5a |
13 | 52044c6206203 |
14 | 2193c7cd93698 |
15 | dd4965975867 |
hex | 6d3fe60da0b6 |
120121210020022 has 8 divisors (see below), whose sum is σ = 180181906146216. Its totient is φ = 60060574637952.
The previous prime is 120121210019957. The next prime is 120121210020029. The reversal of 120121210020022 is 220020012121021.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 120121210019978 and 120121210020005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120121210020029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9870123 + ... + 18375574.
It is an arithmetic number, because the mean of its divisors is an integer number (22522738268277).
Almost surely, 2120121210020022 is an apocalyptic number.
120121210020022 is a deficient number, since it is larger than the sum of its proper divisors (60060696126194).
120121210020022 is a wasteful number, since it uses less digits than its factorization.
120121210020022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30372062.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 120121210020022 its reverse (220020012121021), we get a palindrome (340141222141043).
The spelling of 120121210020022 in words is "one hundred twenty trillion, one hundred twenty-one billion, two hundred ten million, twenty thousand, twenty-two".
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