Base | Representation |
---|---|
bin | 11011010011111111110111… |
… | …111101011001100111110001 |
3 | 120202022111121121002201011112 |
4 | 123103333313331121213301 |
5 | 111221032323132412223 |
6 | 1103251020551123105 |
7 | 34205331002636102 |
oct | 3323776775314761 |
9 | 522274547081145 |
10 | 120121510435313 |
11 | 35302279096782 |
12 | 1158042a973495 |
13 | 520454351b03a |
14 | 2193caac343a9 |
15 | dd4982017778 |
hex | 6d3ff7f599f1 |
120121510435313 has 2 divisors, whose sum is σ = 120121510435314. Its totient is φ = 120121510435312.
The previous prime is 120121510435253. The next prime is 120121510435373. The reversal of 120121510435313 is 313534015121021.
It is a balanced prime because it is at equal distance from previous prime (120121510435253) and next prime (120121510435373).
It can be written as a sum of positive squares in only one way, i.e., 86001752806369 + 34119757628944 = 9273713^2 + 5841212^2 .
It is an emirp because it is prime and its reverse (313534015121021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120121510435313 - 26 = 120121510435249 is a prime.
It is a super-2 number, since 2×1201215104353132 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120121510435313.
It is not a weakly prime, because it can be changed into another prime (120121510435373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060755217656 + 60060755217657.
It is an arithmetic number, because the mean of its divisors is an integer number (60060755217657).
Almost surely, 2120121510435313 is an apocalyptic number.
It is an amenable number.
120121510435313 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121510435313 is an equidigital number, since it uses as much as digits as its factorization.
120121510435313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 120121510435313 its reverse (313534015121021), we get a palindrome (433655525556334).
The spelling of 120121510435313 in words is "one hundred twenty trillion, one hundred twenty-one billion, five hundred ten million, four hundred thirty-five thousand, three hundred thirteen".
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