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120122000983 is a prime number
BaseRepresentation
bin110111111011111010…
…1000100011001010111
3102111001111201220101101
41233313311010121113
53432002213012413
6131103331210531
711451510106255
oct1576765043127
9374044656341
10120122000983
1146a41813286
121b344746a47
13b434561cba
145b576235d5
1531d0a53edd
hex1bf7d44657

120122000983 has 2 divisors, whose sum is σ = 120122000984. Its totient is φ = 120122000982.

The previous prime is 120122000981. The next prime is 120122000989. The reversal of 120122000983 is 389000221021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120122000983 - 21 = 120122000981 is a prime.

Together with 120122000981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120122000981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061000491 + 60061000492.

It is an arithmetic number, because the mean of its divisors is an integer number (60061000492).

Almost surely, 2120122000983 is an apocalyptic number.

120122000983 is a deficient number, since it is larger than the sum of its proper divisors (1).

120122000983 is an equidigital number, since it uses as much as digits as its factorization.

120122000983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

The spelling of 120122000983 in words is "one hundred twenty billion, one hundred twenty-two million, nine hundred eighty-three", and thus it is an aban number.