Base | Representation |
---|---|
bin | 11011010100000000010110… |
… | …011001011110010001110101 |
3 | 120202022112221012000201101012 |
4 | 123110000112121132101311 |
5 | 111221034344401022101 |
6 | 1103251143352442005 |
7 | 34205346443415155 |
oct | 3324002631362165 |
9 | 522275835021335 |
10 | 120122021110901 |
11 | 35302510384917 |
12 | 115805519a9305 |
13 | 52045c5270344 |
14 | 2193d189a8765 |
15 | dd49b1c8dbbb |
hex | 6d401665e475 |
120122021110901 has 2 divisors, whose sum is σ = 120122021110902. Its totient is φ = 120122021110900.
The previous prime is 120122021110891. The next prime is 120122021111041. The reversal of 120122021110901 is 109011120221021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100709273230801 + 19412747880100 = 10035401^2 + 4405990^2 .
It is a cyclic number.
It is not a de Polignac number, because 120122021110901 - 230 = 120120947369077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120122021110501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061010555450 + 60061010555451.
It is an arithmetic number, because the mean of its divisors is an integer number (60061010555451).
Almost surely, 2120122021110901 is an apocalyptic number.
It is an amenable number.
120122021110901 is a deficient number, since it is larger than the sum of its proper divisors (1).
120122021110901 is an equidigital number, since it uses as much as digits as its factorization.
120122021110901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 23.
Adding to 120122021110901 its reverse (109011120221021), we get a palindrome (229133141331922).
The spelling of 120122021110901 in words is "one hundred twenty trillion, one hundred twenty-two billion, twenty-one million, one hundred ten thousand, nine hundred one".
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