1201221660437 has 2 divisors, whose sum is σ = 1201221660438. Its totient is φ = 1201221660436.

The previous prime is 1201221660413. The next prime is 1201221660461. The reversal of 1201221660437 is 7340661221021.

It is a balanced prime because it is at equal distance from previous prime (1201221660413) and next prime (1201221660461).

It can be written as a sum of positive squares in only one way, i.e., 1069137388081 + 132084272356 = 1033991^2 + 363434^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201221660437 - 2³² = 1196926693141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201221660397 and 1201221660406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201221660137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610830218 + 600610830219.

It is an arithmetic number, because the mean of its divisors is an integer number (600610830219).

Almost surely, 2^{1201221660437} is an apocalyptic number.

It is an amenable number.

1201221660437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201221660437 is an equidigital number, since it uses as much as digits as its factorization.

1201221660437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 35.

Adding to 1201221660437 its reverse (7340661221021), we get a palindrome (8541882881458).

The spelling of 1201221660437 in words is "one trillion, two hundred one billion, two hundred twenty-one million, six hundred sixty thousand, four hundred thirty-seven".