1201222194817 has 2 divisors, whose sum is σ = 1201222194818. Its totient is φ = 1201222194816.

The previous prime is 1201222194769. The next prime is 1201222194857. The reversal of 1201222194817 is 7184912221021.

It is a happy number.

It is an a-pointer prime, because the next prime (1201222194857) can be obtained adding 1201222194817 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1201213808001 + 8386816 = 1095999^2 + 2896^2 .

It is an emirp because it is prime and its reverse (7184912221021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201222194817 is a prime.

It is a super-2 number, since 2×1201222194817² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1201222194817.

It is not a weakly prime, because it can be changed into another prime (1201222194857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600611097408 + 600611097409.

It is an arithmetic number, because the mean of its divisors is an integer number (600611097409).

Almost surely, 2^{1201222194817} is an apocalyptic number.

It is an amenable number.

1201222194817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201222194817 is an equidigital number, since it uses as much as digits as its factorization.

1201222194817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 40.

The spelling of 1201222194817 in words is "one trillion, two hundred one billion, two hundred twenty-two million, one hundred ninety-four thousand, eight hundred seventeen".