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12012222020 = 2252939204359
BaseRepresentation
bin10110010111111101…
…11111011001000100
31011000011010002210212
423023332333121010
5144100112101040
65303543334552
7603450126311
oct131376773104
934004102725
1012012222020
11510464a217
1223b2a51458
1311958538a6
1481d4bdd08
154a4886d65
hex2cbfbf644

12012222020 has 24 divisors (see below), whose sum is σ = 25234372800. Its totient is φ = 4803230432.

The previous prime is 12012222017. The next prime is 12012222091. The reversal of 12012222020 is 2022221021.

It is a junction number, because it is equal to n+sod(n) for n = 12012221986 and 12012222004.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43400 + ... + 160959.

It is an arithmetic number, because the mean of its divisors is an integer number (1051432200).

Almost surely, 212012222020 is an apocalyptic number.

12012222020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12012222020 is an abundant number, since it is smaller than the sum of its proper divisors (13222150780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012222020 is a wasteful number, since it uses less digits than its factorization.

12012222020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207307 (or 207305 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 14.

Adding to 12012222020 its reverse (2022221021), we get a palindrome (14034443041).

Subtracting from 12012222020 its reverse (2022221021), we obtain a palindrome (9990000999).

The spelling of 12012222020 in words is "twelve billion, twelve million, two hundred twenty-two thousand, twenty".

Divisors: 1 2 4 5 10 20 2939 5878 11756 14695 29390 58780 204359 408718 817436 1021795 2043590 4087180 600611101 1201222202 2402444404 3003055505 6006111010 12012222020