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12012524261999 is a prime number
BaseRepresentation
bin1010111011001110001000…
…1111011101001001101111
31120112101102110200112101222
42232303202033131021233
53033303122202340444
641314251044253555
72346606356332622
oct256634217351157
946471373615358
1012012524261999
113911534864258
1214201360a12bb
13691a123527c1
142d75a30a9db9
1515c7176eceee
hexaece23dd26f

12012524261999 has 2 divisors, whose sum is σ = 12012524262000. Its totient is φ = 12012524261998.

The previous prime is 12012524261993. The next prime is 12012524262031. The reversal of 12012524261999 is 99916242521021.

It is a weak prime.

It is an emirp because it is prime and its reverse (99916242521021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012524261999 is a prime.

It is a super-2 number, since 2×120125242619992 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12012524261999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012524261993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006262130999 + 6006262131000.

It is an arithmetic number, because the mean of its divisors is an integer number (6006262131000).

Almost surely, 212012524261999 is an apocalyptic number.

12012524261999 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012524261999 is an equidigital number, since it uses as much as digits as its factorization.

12012524261999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1399680, while the sum is 53.

The spelling of 12012524261999 in words is "twelve trillion, twelve billion, five hundred twenty-four million, two hundred sixty-one thousand, nine hundred ninety-nine".