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12013030333200 = 24352132265133997
BaseRepresentation
bin1010111011010000000001…
…1001111101101100010000
31120112102201201221121120210
42232310000121331230100
53033310141231130300
641314413203204120
72346625043014101
oct256640031755420
946472651847523
1012013030333200
113911774498016
121420257676640
13691a93152110
142d76103a23a8
1515c746d65050
hexaed0067db10

12013030333200 has 240 divisors, whose sum is σ = 41444923007936. Its totient is φ = 2956836096000.

The previous prime is 12013030333103. The next prime is 12013030333231. The reversal of 12013030333200 is 233303031021.

It is a tau number, because it is divible by the number of its divisors (240).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 353338602 + ... + 353372598.

Almost surely, 212013030333200 is an apocalyptic number.

12013030333200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12013030333200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20722461503968).

12013030333200 is an abundant number, since it is smaller than the sum of its proper divisors (29431892674736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013030333200 is a wasteful number, since it uses less digits than its factorization.

12013030333200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56682 (or 56671 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 12013030333200 its reverse (233303031021), we get a palindrome (12246333364221).

The spelling of 12013030333200 in words is "twelve trillion, thirteen billion, thirty million, three hundred thirty-three thousand, two hundred".