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120130319 is a prime number
BaseRepresentation
bin1110010100100…
…00101100001111
322101001020211002
413022100230033
5221223132234
615530450515
72656043111
oct712205417
9271036732
10120130319
11618a0761
1234293a3b
131bb7133a
1411d513b1
15a82e27e
hex7290b0f

120130319 has 2 divisors, whose sum is σ = 120130320. Its totient is φ = 120130318.

The previous prime is 120130303. The next prime is 120130321. The reversal of 120130319 is 913031021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120130319 - 24 = 120130303 is a prime.

It is a super-2 number, since 2×1201303192 = 28862587086083522, which contains 22 as substring.

Together with 120130321, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120130319.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120130019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065159 + 60065160.

It is an arithmetic number, because the mean of its divisors is an integer number (60065160).

Almost surely, 2120130319 is an apocalyptic number.

120130319 is a deficient number, since it is larger than the sum of its proper divisors (1).

120130319 is an equidigital number, since it uses as much as digits as its factorization.

120130319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

The square root of 120130319 is about 10960.3977573809. The cubic root of 120130319 is about 493.4209026537.

The spelling of 120130319 in words is "one hundred twenty million, one hundred thirty thousand, three hundred nineteen".