Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11010111001001101 |
3 | 1011000012210210010011 |
4 | 23030002122321031 |
5 | 144100324333401 |
6 | 5304014513221 |
7 | 603460562452 |
oct | 131402327115 |
9 | 34005723104 |
10 | 12013121101 |
11 | 5105103763 |
12 | 23b3205811 |
13 | 1195aa9ba7 |
14 | 81d675829 |
15 | 4a49b3451 |
hex | 2cc09ae4d |
12013121101 has 2 divisors, whose sum is σ = 12013121102. Its totient is φ = 12013121100.
The previous prime is 12013121083. The next prime is 12013121123. The reversal of 12013121101 is 10112131021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8706756100 + 3306365001 = 93310^2 + 57501^2 .
It is an emirp because it is prime and its reverse (10112131021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12013121101 - 227 = 11878903373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013121161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006560550 + 6006560551.
It is an arithmetic number, because the mean of its divisors is an integer number (6006560551).
Almost surely, 212013121101 is an apocalyptic number.
It is an amenable number.
12013121101 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013121101 is an equidigital number, since it uses as much as digits as its factorization.
12013121101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 12013121101 its reverse (10112131021), we get a palindrome (22125252122).
The spelling of 12013121101 in words is "twelve billion, thirteen million, one hundred twenty-one thousand, one hundred one".
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