Base | Representation |
---|---|
bin | 1010111011010000010111… |
… | …0100010100111101001000 |
3 | 1120112102222001210120210210 |
4 | 2232310011310110331020 |
5 | 3033310333002132222 |
6 | 41314430205241120 |
7 | 2346630224536521 |
oct | 256640564247510 |
9 | 46472861716723 |
10 | 12013121130312 |
11 | 3911810773255 |
12 | 1420281b631a0 |
13 | 691aa8bc2b13 |
14 | 2d761c479848 |
15 | 15c74ececd0c |
hex | aed05d14f48 |
12013121130312 has 64 divisors (see below), whose sum is σ = 31851314052480. Its totient is φ = 3762674076672.
The previous prime is 12013121130281. The next prime is 12013121130313. The reversal of 12013121130312 is 21303112131021.
It is not an unprimeable number, because it can be changed into a prime (12013121130313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23766148 + ... + 24266355.
It is an arithmetic number, because the mean of its divisors is an integer number (497676782070).
Almost surely, 212013121130312 is an apocalyptic number.
12013121130312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12013121130312 is an abundant number, since it is smaller than the sum of its proper divisors (19838192922168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013121130312 is a wasteful number, since it uses less digits than its factorization.
12013121130312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48033142 (or 48033138 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12013121130312 its reverse (21303112131021), we get a palindrome (33316233261333).
The spelling of 12013121130312 in words is "twelve trillion, thirteen billion, one hundred twenty-one million, one hundred thirty thousand, three hundred twelve".
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