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120131213012143 is a prime number
BaseRepresentation
bin11011010100001000111010…
…010001110010110010101111
3120202100102122210012200101221
4123110020322101302302233
5111221212211012342033
61103255303431044211
734206123306323104
oct3324107221626257
9522312583180357
10120131213012143
11353063a7a27313
1211582298210667
13520542b700568
14219454b694aab
15dd4d4dc2512d
hex6d423a472caf

120131213012143 has 2 divisors, whose sum is σ = 120131213012144. Its totient is φ = 120131213012142.

The previous prime is 120131213012117. The next prime is 120131213012233. The reversal of 120131213012143 is 341210312131021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120131213012143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120131213012743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065606506071 + 60065606506072.

It is an arithmetic number, because the mean of its divisors is an integer number (60065606506072).

Almost surely, 2120131213012143 is an apocalyptic number.

120131213012143 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131213012143 is an equidigital number, since it uses as much as digits as its factorization.

120131213012143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 120131213012143 its reverse (341210312131021), we get a palindrome (461341525143164).

The spelling of 120131213012143 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred thirteen million, twelve thousand, one hundred forty-three".