12013132000112 has 40 divisors (see below), whose sum is σ = 24768429228000. Its totient is φ = 5624830328832.

The previous prime is 12013132000097. The next prime is 12013132000117. The reversal of 12013132000112 is 21100023131021.

It is a super-2 number, since 2×12013132000112² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013132000117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110915537 + ... + 111023792.

It is an arithmetic number, because the mean of its divisors is an integer number (619210730700).

Almost surely, 2^{12013132000112} is an apocalyptic number.

It is an amenable number.

12013132000112 is an abundant number, since it is smaller than the sum of its proper divisors (12755297227888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013132000112 is a wasteful number, since it uses less digits than its factorization.

12013132000112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221939553 (or 221939547 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12013132000112 its reverse (21100023131021), we get a palindrome (33113155131133).

The spelling of 12013132000112 in words is "twelve trillion, thirteen billion, one hundred thirty-two million, one hundred twelve", and thus it is an aban number.