1201314181 has 2 divisors, whose sum is σ = 1201314182. Its totient is φ = 1201314180.

The previous prime is 1201314167. The next prime is 1201314203. The reversal of 1201314181 is 1814131021.

It is an a-pointer prime, because the next prime (1201314203) can be obtained adding 1201314181 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 774230625 + 427083556 = 27825^2 + 20666^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201314181 is a prime.

It is a super-3 number, since 3×1201314181³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201314131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600657090 + 600657091.

It is an arithmetic number, because the mean of its divisors is an integer number (600657091).

Almost surely, 2^1201314181 is an apocalyptic number.

It is an amenable number.

1201314181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201314181 is an equidigital number, since it uses as much as digits as its factorization.

1201314181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 22.

The square root of 1201314181 is about 34659.9795297112. The cubic root of 1201314181 is about 1063.0463514629.

The spelling of 1201314181 in words is "one billion, two hundred one million, three hundred fourteen thousand, one hundred eighty-one".