120132011313901 has 2 divisors, whose sum is σ = 120132011313902. Its totient is φ = 120132011313900.

The previous prime is 120132011313883. The next prime is 120132011313913. The reversal of 120132011313901 is 109313110231021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107969348088900 + 12162663225001 = 10390830^2 + 3487501^2 .

It is a cyclic number.

It is not a de Polignac number, because 120132011313901 - 2³⁹ = 119582255500013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120132011313901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132011343901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066005656950 + 60066005656951.

It is an arithmetic number, because the mean of its divisors is an integer number (60066005656951).

Almost surely, 2^{120132011313901} is an apocalyptic number.

It is an amenable number.

120132011313901 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132011313901 is an equidigital number, since it uses as much as digits as its factorization.

120132011313901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 28.

Adding to 120132011313901 its reverse (109313110231021), we get a palindrome (229445121544922).

The spelling of 120132011313901 in words is "one hundred twenty trillion, one hundred thirty-two billion, eleven million, three hundred thirteen thousand, nine hundred one".