120132030130999 has 2 divisors, whose sum is σ = 120132030131000. Its totient is φ = 120132030130998.

The previous prime is 120132030130997. The next prime is 120132030131117. The reversal of 120132030130999 is 999031030231021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120132030130999 - 2¹ = 120132030130997 is a prime.

It is a super-2 number, since 2×120132030130999² (a number of 29 digits) contains 22 as substring.

Together with 120132030130997, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132030130997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066015065499 + 60066015065500.

It is an arithmetic number, because the mean of its divisors is an integer number (60066015065500).

Almost surely, 2^{120132030130999} is an apocalyptic number.

120132030130999 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132030130999 is an equidigital number, since it uses as much as digits as its factorization.

120132030130999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 43.

The spelling of 120132030130999 in words is "one hundred twenty trillion, one hundred thirty-two billion, thirty million, one hundred thirty thousand, nine hundred ninety-nine".