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120132232544399 is a prime number
BaseRepresentation
bin11011010100001001110111…
…000011000000000010001111
3120202100112021211122021201212
4123110021313003000002033
5111221221303012410044
61103255552531125035
734206160466234255
oct3324116703000217
9522315254567655
10120132232544399
1135306880480a59
121158252174377b
1352055619b8c9a
142194606c485d5
15dd4dad4b3a9e
hex6d42770c008f

120132232544399 has 2 divisors, whose sum is σ = 120132232544400. Its totient is φ = 120132232544398.

The previous prime is 120132232544333. The next prime is 120132232544449. The reversal of 120132232544399 is 993445232231021.

It is an a-pointer prime, because the next prime (120132232544449) can be obtained adding 120132232544399 to its sum of digits (50).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120132232544399 - 244 = 102540046499983 is a prime.

It is a super-2 number, since 2×1201322325443992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132232544699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066116272199 + 60066116272200.

It is an arithmetic number, because the mean of its divisors is an integer number (60066116272200).

Almost surely, 2120132232544399 is an apocalyptic number.

120132232544399 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132232544399 is an equidigital number, since it uses as much as digits as its factorization.

120132232544399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 50.

The spelling of 120132232544399 in words is "one hundred twenty trillion, one hundred thirty-two billion, two hundred thirty-two million, five hundred forty-four thousand, three hundred ninety-nine".