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120132302231352 = 2335005512592973
BaseRepresentation
bin11011010100001001111011…
…001100110101011100111000
3120202100112110200202202021010
4123110021323030311130320
5111221221423332400402
61103300003500513520
734206162303455235
oct3324117314653470
9522315420682233
10120132302231352
1135306906848884
1211582540b4b8a0
135205573278178
1421946121c878c
15dd4db467ba6c
hex6d427b335738

120132302231352 has 16 divisors (see below), whose sum is σ = 300330755578440. Its totient is φ = 40044100743776.

The previous prime is 120132302231321. The next prime is 120132302231393. The reversal of 120132302231352 is 253132203231021.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2502756296463 + ... + 2502756296510.

Almost surely, 2120132302231352 is an apocalyptic number.

120132302231352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120132302231352 is an abundant number, since it is smaller than the sum of its proper divisors (180198453347088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120132302231352 is a wasteful number, since it uses less digits than its factorization.

120132302231352 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5005512592982 (or 5005512592978 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 120132302231352 its reverse (253132203231021), we get a palindrome (373264505462373).

The spelling of 120132302231352 in words is "one hundred twenty trillion, one hundred thirty-two billion, three hundred two million, two hundred thirty-one thousand, three hundred fifty-two".

Divisors: 1 2 3 4 6 8 12 24 5005512592973 10011025185946 15016537778919 20022050371892 30033075557838 40044100743784 60066151115676 120132302231352