Base | Representation |
---|---|
bin | 1010111011010000110001… |
… | …1111000101001010001111 |
3 | 1120112110020212022012200102 |
4 | 2232310030133011022033 |
5 | 3033311100122013403 |
6 | 41314445243121315 |
7 | 2346633053452445 |
oct | 256641437051217 |
9 | 46473225265612 |
10 | 12013233001103 |
11 | 3911868932454 |
12 | 14202b351323b |
13 | 691ac6131859 |
14 | 2d762d27ab95 |
15 | 15c759a49b88 |
hex | aed0c7c528f |
12013233001103 has 2 divisors, whose sum is σ = 12013233001104. Its totient is φ = 12013233001102.
The previous prime is 12013233001093. The next prime is 12013233001177. The reversal of 12013233001103 is 30110033231021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12013233001103 - 210 = 12013233000079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013233061103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616500551 + 6006616500552.
It is an arithmetic number, because the mean of its divisors is an integer number (6006616500552).
Almost surely, 212013233001103 is an apocalyptic number.
12013233001103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013233001103 is an equidigital number, since it uses as much as digits as its factorization.
12013233001103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12013233001103 its reverse (30110033231021), we get a palindrome (42123266232124).
The spelling of 12013233001103 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, one thousand, one hundred three".
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