12013233000079 has 2 divisors, whose sum is σ = 12013233000080. Its totient is φ = 12013233000078.

The previous prime is 12013233000077. The next prime is 12013233000107. The reversal of 12013233000079 is 97000033231021.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12013233000079 - 2¹ = 12013233000077 is a prime.

It is a super-2 number, since 2×12013233000079² (a number of 27 digits) contains 22 as substring.

Together with 12013233000077, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 12013233000079.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013233000071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616500039 + 6006616500040.

It is an arithmetic number, because the mean of its divisors is an integer number (6006616500040).

Almost surely, 2^{12013233000079} is an apocalyptic number.

12013233000079 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013233000079 is an equidigital number, since it uses as much as digits as its factorization.

12013233000079 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 31.

The spelling of 12013233000079 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, seventy-nine", and thus it is an aban number.