12013233001409 has 2 divisors, whose sum is σ = 12013233001410. Its totient is φ = 12013233001408.

The previous prime is 12013233001391. The next prime is 12013233001411. The reversal of 12013233001409 is 90410033231021.

12013233001409 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6759854400784 + 5253378600625 = 2599972^2 + 2292025^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013233001409 - 2²⁰ = 12013231952833 is a prime.

It is a super-2 number, since 2×12013233001409² (a number of 27 digits) contains 22 as substring.

Together with 12013233001411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12013233601409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616500704 + 6006616500705.

It is an arithmetic number, because the mean of its divisors is an integer number (6006616500705).

Almost surely, 2^{12013233001409} is an apocalyptic number.

It is an amenable number.

12013233001409 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013233001409 is an equidigital number, since it uses as much as digits as its factorization.

12013233001409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 12013233001409 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, one thousand, four hundred nine".