Base | Representation |
---|---|
bin | 1010111011010000110001… |
… | …1111000101001111000010 |
3 | 1120112110020212022020002210 |
4 | 2232310030133011033002 |
5 | 3033311100122021120 |
6 | 41314445243122550 |
7 | 2346633053453364 |
oct | 256641437051702 |
9 | 46473225266083 |
10 | 12013233001410 |
11 | 3911868932703 |
12 | 14202b3513456 |
13 | 691ac6131a34 |
14 | 2d762d27ad34 |
15 | 15c759a49ce0 |
hex | aed0c7c53c2 |
12013233001410 has 32 divisors (see below), whose sum is σ = 28843484374080. Its totient is φ = 3202226003648.
The previous prime is 12013233001409. The next prime is 12013233001411. The reversal of 12013233001410 is 1410033231021.
12013233001410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (12013233001409) and next prime (12013233001411).
It is a super-4 number, since 4×120132330014104 (a number of 53 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (12013233001411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81349797 + ... + 81497336.
It is an arithmetic number, because the mean of its divisors is an integer number (901358886690).
Almost surely, 212013233001410 is an apocalyptic number.
12013233001410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12013233001410 is an abundant number, since it is smaller than the sum of its proper divisors (16830251372670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013233001410 is a wasteful number, since it uses less digits than its factorization.
12013233001410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162849602.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12013233001410 its reverse (1410033231021), we get a palindrome (13423266232431).
The spelling of 12013233001410 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, one thousand, four hundred ten".
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