12013312012030 has 64 divisors (see below), whose sum is σ = 24943724213760. Its totient is φ = 4080424118400.

The previous prime is 12013312012019. The next prime is 12013312012043. The reversal of 12013312012030 is 3021021331021.

It is a junction number, because it is equal to n+sod(n) for n = 12013312011989 and 12013312012007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50016925 + ... + 50256535.

It is an arithmetic number, because the mean of its divisors is an integer number (389745690840).

Almost surely, 2^{12013312012030} is an apocalyptic number.

12013312012030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12013312012030 is an abundant number, since it is smaller than the sum of its proper divisors (12930412201730).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013312012030 is a wasteful number, since it uses less digits than its factorization.

12013312012030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246305.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12013312012030 its reverse (3021021331021), we get a palindrome (15034333343051).

The spelling of 12013312012030 in words is "twelve trillion, thirteen billion, three hundred twelve million, twelve thousand, thirty".