Base | Representation |
---|---|
bin | 11011010100001010111000… |
… | …011101111000011001000111 |
3 | 120202100122010022220101201112 |
4 | 123110022320131320121013 |
5 | 111221231030002010043 |
6 | 1103300253455515235 |
7 | 34206226624341116 |
oct | 3324127035703107 |
9 | 522318108811645 |
10 | 120133330110023 |
11 | 35307293a8328a |
12 | 11582789228b1b |
13 | 52056a81c68b9 |
14 | 21946ac911c7d |
15 | dd4e24a18518 |
hex | 6d42b8778647 |
120133330110023 has 2 divisors, whose sum is σ = 120133330110024. Its totient is φ = 120133330110022.
The previous prime is 120133330109911. The next prime is 120133330110061. The reversal of 120133330110023 is 320011033331021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120133330110023 - 212 = 120133330105927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120133330110923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066665055011 + 60066665055012.
It is an arithmetic number, because the mean of its divisors is an integer number (60066665055012).
Almost surely, 2120133330110023 is an apocalyptic number.
120133330110023 is a deficient number, since it is larger than the sum of its proper divisors (1).
120133330110023 is an equidigital number, since it uses as much as digits as its factorization.
120133330110023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 120133330110023 its reverse (320011033331021), we get a palindrome (440144363441044).
The spelling of 120133330110023 in words is "one hundred twenty trillion, one hundred thirty-three billion, three hundred thirty million, one hundred ten thousand, twenty-three".
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