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120133601501 is a prime number
BaseRepresentation
bin110111111100010000…
…1010100100011011101
3102111002022120021022012
41233320201110203131
53432013200222001
6131104424001005
711452010523104
oct1577041244335
9374068507265
10120133601501
1146a48316991
121b348600165
13b436a94204
145b58da303b
1531d1a962bb
hex1bf88548dd

120133601501 has 2 divisors, whose sum is σ = 120133601502. Its totient is φ = 120133601500.

The previous prime is 120133601491. The next prime is 120133601503. The reversal of 120133601501 is 105106331021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100599346276 + 19534255225 = 317174^2 + 139765^2 .

It is a cyclic number.

It is not a de Polignac number, because 120133601501 - 222 = 120129407197 is a prime.

Together with 120133601503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120133601503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066800750 + 60066800751.

It is an arithmetic number, because the mean of its divisors is an integer number (60066800751).

Almost surely, 2120133601501 is an apocalyptic number.

It is an amenable number.

120133601501 is a deficient number, since it is larger than the sum of its proper divisors (1).

120133601501 is an equidigital number, since it uses as much as digits as its factorization.

120133601501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 120133601501 its reverse (105106331021), we get a palindrome (225239932522).

The spelling of 120133601501 in words is "one hundred twenty billion, one hundred thirty-three million, six hundred one thousand, five hundred one".