Base | Representation |
---|---|
bin | 11011010100001011101001… |
… | …000011111110010100001101 |
3 | 120202100201020011000112020022 |
4 | 123110023221003332110031 |
5 | 111221234212210332000 |
6 | 1103300510422231525 |
7 | 34206256054245041 |
oct | 3324135103762415 |
9 | 522321204015208 |
10 | 120134145402125 |
11 | 35307672209308 |
12 | 115829762855a5 |
13 | 52057a80a206a |
14 | 2194748cdc021 |
15 | dd4e713b1585 |
hex | 6d42e90fe50d |
120134145402125 has 32 divisors (see below), whose sum is σ = 150713569593600. Its totient is φ = 95603580072000.
The previous prime is 120134145402097. The next prime is 120134145402199. The reversal of 120134145402125 is 521204541431021.
It is not a de Polignac number, because 120134145402125 - 214 = 120134145385741 is a prime.
It is a super-2 number, since 2×1201341454021252 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 114424814 + ... + 115469936.
It is an arithmetic number, because the mean of its divisors is an integer number (4709799049800).
Almost surely, 2120134145402125 is an apocalyptic number.
It is an amenable number.
120134145402125 is a deficient number, since it is larger than the sum of its proper divisors (30579424191475).
120134145402125 is a wasteful number, since it uses less digits than its factorization.
120134145402125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1049958 (or 1049948 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 120134145402125 its reverse (521204541431021), we get a palindrome (641338686833146).
The spelling of 120134145402125 in words is "one hundred twenty trillion, one hundred thirty-four billion, one hundred forty-five million, four hundred two thousand, one hundred twenty-five".
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