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120134432128013 is a prime number
BaseRepresentation
bin11011010100001011111010…
…001001101111110000001101
3120202100201222010112201012122
4123110023322021233300031
5111221240304111044023
61103300555103542325
734206266135340422
oct3324137211576015
9522321863481178
10120134432128013
11353077aa046756
1211582a362ba9a5
135205822602c54
142194775017d49
15dd4e8b64c2c8
hex6d42fa26fc0d

120134432128013 has 2 divisors, whose sum is σ = 120134432128014. Its totient is φ = 120134432128012.

The previous prime is 120134432127989. The next prime is 120134432128019. The reversal of 120134432128013 is 310821234431021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105775198075849 + 14359234052164 = 10284707^2 + 3789358^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120134432128013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120134432128019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067216064006 + 60067216064007.

It is an arithmetic number, because the mean of its divisors is an integer number (60067216064007).

Almost surely, 2120134432128013 is an apocalyptic number.

It is an amenable number.

120134432128013 is a deficient number, since it is larger than the sum of its proper divisors (1).

120134432128013 is an equidigital number, since it uses as much as digits as its factorization.

120134432128013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 120134432128013 its reverse (310821234431021), we get a palindrome (430955666559034).

The spelling of 120134432128013 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred thirty-two million, one hundred twenty-eight thousand, thirteen".