Search a number
-
+
12013443213293 is a prime number
BaseRepresentation
bin1010111011010001100100…
…0000111110011111101101
31120112110210111212002121002
42232310121000332133231
53033312012430311133
641314522152450045
72346641215312124
oct256643100763755
946473714762532
1012013443213293
11391196655aa35
1214203519a9925
13691b2a853172
142d764d15aabb
1515c76d21ece8
hexaed1903e7ed

12013443213293 has 2 divisors, whose sum is σ = 12013443213294. Its totient is φ = 12013443213292.

The previous prime is 12013443213197. The next prime is 12013443213307. The reversal of 12013443213293 is 39231234431021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12005545869604 + 7897343689 = 3464902^2 + 88867^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013443213293 - 212 = 12013443209197 is a prime.

It is a super-3 number, since 3×120134432132933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013443213193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006721606646 + 6006721606647.

It is an arithmetic number, because the mean of its divisors is an integer number (6006721606647).

Almost surely, 212013443213293 is an apocalyptic number.

It is an amenable number.

12013443213293 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013443213293 is an equidigital number, since it uses as much as digits as its factorization.

12013443213293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 38.

The spelling of 12013443213293 in words is "twelve trillion, thirteen billion, four hundred forty-three million, two hundred thirteen thousand, two hundred ninety-three".