120134716837 has 2 divisors, whose sum is σ = 120134716838. Its totient is φ = 120134716836.

The previous prime is 120134716787. The next prime is 120134716853. The reversal of 120134716837 is 738617431021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72883260961 + 47251455876 = 269969^2 + 217374^2 .

It is an emirp because it is prime and its reverse (738617431021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120134716837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120134716793 and 120134716802.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120134714837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067358418 + 60067358419.

It is an arithmetic number, because the mean of its divisors is an integer number (60067358419).

Almost surely, 2^120134716837 is an apocalyptic number.

It is an amenable number.

120134716837 is a deficient number, since it is larger than the sum of its proper divisors (1).

120134716837 is an equidigital number, since it uses as much as digits as its factorization.

120134716837 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 169344, while the sum is 43.

The spelling of 120134716837 in words is "one hundred twenty billion, one hundred thirty-four million, seven hundred sixteen thousand, eight hundred thirty-seven".