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120135320114052 = 22310011276676171
BaseRepresentation
bin11011010100001100101111…
…000101001001001110000100
3120202100211021000110002001110
4123110030233011021032010
5111221244113422122202
61103301223144325020
734206330140161125
oct3324145705111604
9522324230402043
10120135320114052
1135308115312811
1211583043773770
135205934581189
14219481ad2804c
15dd4ede5a426c
hex6d432f149384

120135320114052 has 12 divisors (see below), whose sum is σ = 280315746932816. Its totient is φ = 40045106704680.

The previous prime is 120135320113973. The next prime is 120135320114081. The reversal of 120135320114052 is 250411023531021.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (12).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5005638338074 + ... + 5005638338097.

Almost surely, 2120135320114052 is an apocalyptic number.

120135320114052 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120135320114052 is an abundant number, since it is smaller than the sum of its proper divisors (160180426818764).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120135320114052 is a wasteful number, since it uses less digits than its factorization.

120135320114052 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10011276676178 (or 10011276676176 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 120135320114052 its reverse (250411023531021), we get a palindrome (370546343645073).

The spelling of 120135320114052 in words is "one hundred twenty trillion, one hundred thirty-five billion, three hundred twenty million, one hundred fourteen thousand, fifty-two".

Divisors: 1 2 3 4 6 12 10011276676171 20022553352342 30033830028513 40045106704684 60067660057026 120135320114052